![]() ![]() Radiometric units are Human Visual System (HVS) neutral "physical" units defined based on Watts (W), while photometric units are HVS weighted units defined based on Lumens (lm). I listed both radiometric and photometric properties/units. Below is a list of different lighting properties/units commonly used in lighting calculations that define the light “brightness”. Light “brightness” is indeed quite poor/ambiguous layman’s definition for brightness of a light source. ![]() The short answer: no, but if you are interested in details, please keep reading (: About lighting units I suspect there isn't a linear relationship which is confusing the issue.Ĭan objective light intensity be calculated from an RGB value? Unlike dark yellow ( #808000) which actually is equal to the red in intensity! That makes sense, thinking about two lights being on rather than one, but looking at the colours I would have guessed they were of somewhat equal intensity. So, for instance, that makes yellow ( #ffff00) twice as intense as red ( #ff0000). My first thought, given that the RGB values correspond to the intensity of the pixel's three lights, is to take the average: (R + G + B) ÷ 3 with something like: (0.21 × R) + (0.72 × G) + (0.07 × B)īut, ignoring human biology and perception, is there an accepted way to calculate the objective, theoretical "light intensity" of an RGB value? (Theoretical because the real value will vary between displays) You can calculate subjective brightness of an RGB value by weighting the three channels according to their perceived brightness, e.g. I think I am asking about radiant intensity, that is, the measurable intensity of energy emitted, not weighted for subjective perception. EDIT: I'm not fully clear on terminology here, what I previously understood to be called "brightness" seems poorly defined. ![]()
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